Modules: Convertir un montant ($500) en mots (Five Hundred Dollars) |
Author(s) Joe Foster |
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NDLT: La conversion en mots est en anglais.
(Q) I'm looking to have Access convert the currency value
"$531.20" into the text "Five hundred thirty one and twenty cents."
(A) Use the following function provided by Joe Foster to
convert the Currency into English words.
Function English (ByVal N As Currency) As String
Const Thousand = 1000@
Const Million = Thousand * Thousand
Const Billion = Thousand * Million
Const Trillion = Thousand * Billion
If (N = 0@) Then English = "zero": Exit Function
Dim Buf As String: If (N < 0@) Then Buf = "negative " Else Buf = ""
Dim Frac As Currency: Frac = Abs(N - Fix(N))
If (N < 0@ Or Frac <> 0@) Then N = Abs(Fix(N))
Dim AtLeastOne As Integer: AtLeastOne = N >= 1
If (N >= Trillion) Then
Debug.Print N
Buf = Buf & EnglishDigitGroup(Int(N / Trillion)) & " trillion"
N = N - Int(N / Trillion) * Trillion
If (N >= 1@) Then Buf = Buf & " "
End If
If (N >= Billion) Then
Debug.Print N
Buf = Buf & EnglishDigitGroup(Int(N / Billion)) & " billion"
N = N - Int(N / Billion) * Billion
If (N >= 1@) Then Buf = Buf & " "
End If
If (N >= Million) Then
Debug.Print N
Buf = Buf & EnglishDigitGroup(N \ Million) & " million"
N = N Mod Million
If (N >= 1@) Then Buf = Buf & " "
End If
If (N >= Thousand) Then
Debug.Print N
Buf = Buf & EnglishDigitGroup(N \ Thousand) & " thousand"
N = N Mod Thousand
If (N >= 1@) Then Buf = Buf & " "
End If
If (N >= 1@) Then
Debug.Print N
Buf = Buf & EnglishDigitGroup(N)
End If
If (Frac = 0@) Then
Buf = Buf & " exactly"
ElseIf (Int(Frac * 100@) = Frac * 100@) Then
If AtLeastOne Then Buf = Buf & " and "
Buf = Buf & Format$(Frac * 100@, "00") & "/100"
Else
If AtLeastOne Then Buf = Buf & " and "
Buf = Buf & Format$(Frac * 10000@, "0000") & "/10000"
End If
English = Buf
End Function
Private Function EnglishDigitGroup (ByVal N As Integer) As String
Const Hundred = " hundred"
Const One = "one"
Const Two = "two"
Const Three = "three"
Const Four = "four"
Const Five = "five"
Const Six = "six"
Const Seven = "seven"
Const Eight = "eight"
Const Nine = "nine"
Dim Buf As String: Buf = ""
Dim Flag As Integer: Flag = False
Select Case (N \ 100)
Case 0: Buf = "": Flag = False
Case 1: Buf = One & Hundred: Flag = True
Case 2: Buf = Two & Hundred: Flag = True
Case 3: Buf = Three & Hundred: Flag = True
Case 4: Buf = Four & Hundred: Flag = True
Case 5: Buf = Five & Hundred: Flag = True
Case 6: Buf = Six & Hundred: Flag = True
Case 7: Buf = Seven & Hundred: Flag = True
Case 8: Buf = Eight & Hundred: Flag = True
Case 9: Buf = Nine & Hundred: Flag = True
End Select
If (Flag <> False) Then N = N Mod 100
If (N > 0) Then
If (Flag <> False) Then Buf = Buf & " "
Else
EnglishDigitGroup = Buf
Exit Function
End If
Select Case (N \ 10)
Case 0, 1: Flag = False
Case 2: Buf = Buf & "twenty": Flag = True
Case 3: Buf = Buf & "thirty": Flag = True
Case 4: Buf = Buf & "forty": Flag = True
Case 5: Buf = Buf & "fifty": Flag = True
Case 6: Buf = Buf & "sixty": Flag = True
Case 7: Buf = Buf & "seventy": Flag = True
Case 8: Buf = Buf & "eighty": Flag = True
Case 9: Buf = Buf & "ninety": Flag = True
End Select
If (Flag <> False) Then N = N Mod 10
If (N > 0) Then
If (Flag <> False) Then Buf = Buf & "-"
Else
EnglishDigitGroup = Buf
Exit Function
End If
Select Case (N)
Case 0:
Case 1: Buf = Buf & One
Case 2: Buf = Buf & Two
Case 3: Buf = Buf & Three
Case 4: Buf = Buf & Four
Case 5: Buf = Buf & Five
Case 6: Buf = Buf & Six
Case 7: Buf = Buf & Seven
Case 8: Buf = Buf & Eight
Case 9: Buf = Buf & Nine
Case 10: Buf = Buf & "ten"
Case 11: Buf = Buf & "eleven"
Case 12: Buf = Buf & "twelve"
Case 13: Buf = Buf & "thirteen"
Case 14: Buf = Buf & "fourteen"
Case 15: Buf = Buf & "fifteen"
Case 16: Buf = Buf & "sixteen"
Case 17: Buf = Buf & "seventeen"
Case 18: Buf = Buf & "eighteen"
Case 19: Buf = Buf & "nineteen"
End Select
EnglishDigitGroup = Buf
End Function
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